sphere inside out
Posted on Tuesday, November 6, 2007 in Uncategorized
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Turning a Sphere Inside Out [VHS] One of the finalists participating in the International Snow Sculpture Championships in Breckenridge, CO will be creating a snow sculpture that illustrates the concept descibed in this movie. In 2002, members of the same team were awarded Second Place. The International Snow Sculpture Championships has been named to the top 200 events internationally by the Events Business News. A list of some of … |
What is the volume of the region within the sphere of the unit (centered at the origin) and above the plane z = 4 / 5?
I know I need to integrate (sqrt (1-x ^ 2 – y ^ 2) – 4 / 5) in the disk of radius 3 / 5. The conversion of these polar coordinates, I have the double integral of (sqrt (1-r ^ 2) -4 / 5) RDR dtheta, with 0 <= r <= 3 / 5 and 0 <= theta <= 2pi. How can I solve this double integral?
I suggest using coordonates spherical (http://en.wikipedia.org/wiki/Multiple_integral # Spherical_coordinates) the integral is much easier = T | 0 ¯ <= Phy <= arctan (0.6/0.8) __ | 0 <= theta <= 2 * 0.8/cos pi __|_( (Phy) <= rho <= 1 are the parameters I've found using trigonometric and has given: SSS (T) Psy ^ 2 * sin (Rho) dRho dphys dTheta resolve and gives 112/3000 * pi
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Turning a Sphere Inside Out [VHS] One of the finalists participating in the International Snow Sculpture Championships in Breckenridge, CO will be creating a snow sculpture that illustrates the concept descibed in this movie. In 2002, members of the same team were awarded Second Place. The International Snow Sculpture Championships has been named to the top 200 events internationally by the Events Business News. A list of some of … |
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